23m^2-25m+2=0

Solution for 23m^2-25m+2=0 equation:

23m^2-25m+2=0

a = 23; b = -25; c = +2;
Δ = b2-4ac
Δ = -252-4·23·2
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-21}{2*23}=\frac{4}{46}
=2/23
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+21}{2*23}=\frac{46}{46}
=1
$